a[j] > a[i] then a[i] is not a Buy point at all. All the persons can be sold a seat ticket until there are vacant seats. I think your solution and mine are same. You add the squares of the chosen elements and perform the modulo operation. of rows) and M(modulus) from the user and convert both values to integer using map() function, Then we create an empty list and name it nums, and we loop K(no. The list consists of Ni elements. Podcast 314: How do digital nomads pay their taxes? Note that you need to take exactly one element from each list, not necessarily the largest element. .MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: Hackerrank Breadth First Search: Shortest Reach Solution. and you sell it at the price of smax. here is more simple and easy to understand algo; My reasoning is, you make profit for every stock bought before the maximum stock price. For example, given [8, 10, 7, 5, 7, 15], the function will return 10, since the buying value of the stock is 5 dollars and sell value is 15 dollars. 0.Start from end of array so that no need to recurse The first line contains 2 space separated integers K and M.The next K lines each contains an integer Ni, denoting the number of elements in the ith list, followed by Ni space separated integers denoting the elements in the list.eval(ez_write_tag([[468,60],'thepoorcoder_com-box-3','ezslot_7',102,'0','0'])); Output a single integer denoting the value Smax. - Then sell all, you will not find a better day. In the above example i have added a list function just for unpacking the values inside the map function. Which was the first magazine presented in electronic form, on a data medium, to be read on a computer? Plot3D doesn't generate the ellipitic paraboloid it's supposed to. A simple solution is to generate all pairs, find their XOR values and finally return the maximum XOR value.. An efficient solution is to consider pattern of binary values from L to R.We can see that first bit from L to R either changes from 0 to 1 or it stays 1 i.e. Is this the highest price so far (from the end), then sell! Your algorithms have become so good at predicting the market that can predict the share price of Wooden Orange Toothpicks Inc. You should have the maximum profit. But the catch is, from a particular village i, you can only move to a village j if and only if \(i < j\) and the profit gain from village j is a multiple of the profit gain from village i. of row ) times. Find the maximized value Smax obtained. Each day, you can either buy one unit of stock, sell any number of stock units you have already bought, or do nothing. Another O(n) solution for this task can be done by using local minimum and maximum finding the best deference (profit) between max and min knowing that max should have greater index then min. Arrays. Find the maximum possible value out of the equation provided. (I've updated my post.) j > i for a i in linear access. Is it correct to say "My teacher yesterday was in Beijing."? If you have any confusion just leave a comment below and I will try to make it clear for you. Each day, you can either buy one share of WOT, sell any number of shares of WOT that you own, or not make any transaction at all. You can verify that the profit calculation is correct with a simple loop (for simplicity imagine it's within the above function). Stock Buy Sell to Maximize Profit. That could also say âminimizeâ, and that would indicate our problem was a minimization problem. The page is a good start for people to solve these problems as the time constraints are rather forgiving. eval(ez_write_tag([[580,400],'thepoorcoder_com-medrectangle-3','ezslot_4',103,'0','0']));Explanation. This can be computed efficiently with the help of a ⦠i.e. The last day (where we start reading) you will always sell. eval(ez_write_tag([[300,250],'thepoorcoder_com-banner-1','ezslot_2',109,'0','0']));And here you go, the greatest number of this list is our answer. 1. Serious alternate form of the Drake Equation, or graffiti? So my question is can anyone think of a more efficient solution to this problem ? I just solved that problem in a contest site. rev 2021.2.18.38600, Stack Overflow works best with JavaScript enabled, Where developers & technologists share private knowledge with coworkers, Programming & related technical career opportunities, Recruit tech talent & build your employer brand, Reach developers & technologists worldwide, In your example "1 3 1 2 4" the result should be 9 not 7 :) Max price is 4 not 2. Approach: In order to maximize the profit, the ticket must be for the seat in a row which has the maximum number of vacant seats and the number of vacant seats in that row will be decrement by 1 as one of the seats has just been sold. Add a description, image, and links to the hackerrank-python topic page so that developers can more easily learn about it. this solution passed 10 of the 11 cases but exceeded the time limit on a last test case (i.e the largest input). The maximum value that you can obtain, will be the answer to the problem. You have to travel to different villages to make some profit. for each element a[i] find a[j] s.t. I agree with the logic of your method but there is no need to do recursive processing or global maxima searches. However I couldn't pass test cases and don't ⦠we vary number of stock units bought and the stock data available from 1 stock to n stock(like previosly, we had only for Google, now we have for 5 other companies as well). Strange Counter Hacker Rank Problem Solution. What do you mean by "now also"? Here's the code in C-like python: (I avoided most pythonic stuff. Is there any meaningful difference between event.getParam("x") and event.getParams().x? Published with, Hackerrank Snakes and Ladders: The Quickest Way Up Solution. @Johan: you rock \m/ thanks for spending time and explaining things in detail :), @Johan how would we change approach if we were to start with a budget of M$ and instead of single stock we had m stocks with prices over n days as given? In theory, this problem is listed under "dynamic programming" what is exactly has to do with dynamic programming here? Again buy on day 4 and sell on day 6. We also need to look at previous best local min (C# implementation). c) merge the profits, e.g 1 4 1 2 3 © 2021 The Poor Coder | Hackerrank Solutions - You have to pick one element from each list so that the value from the equation below is maximized: Xi denotes the element picked from the ith list . In each village, you gain some profit. Join over 7 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. Contribute to yznpku/HackerRank development by creating an account on GitHub. sell at global maxima's..but recursion is not required... if ith element is global maxima...sell all stocks before i! Editorial. HackerRank concepts & solutions. Given a 2D array arr[][] with each row of the form {l, r}, the task is to find a pair (i, j) such that the⦠Read More. in example, 1 3 1 2 4, why highest stock price is on day 2? So in your case, instead of checking from [1,1000] if you just check from [1,103] and find the largest multiples of these numbers less than or equal to 26,103, 59 and calculate the profits appropriately. By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy. Let's use the max function for finding the biggest number. And as you pointed out it is exactly the same solution as Johan's but requires extra O(n) space. What is the algorithm and underlying structure of this recursive DP algorithm about buying and selling stock? Now the following gives us all the possible ways of picking K numbers from our nums variable, Now our task is to sum each list and find the remainder after diving by M. For which we will use lambda, sum and map function. Obviously best case in Trial 1 is to buy for 4 days and ⦠Picking 5 from the 1st list, 9 from the 2nd list and 10 from the 3rd list gives the maximum S value equal to (52 + 92 + 10 2)%1000 =206. Example 1: Input: prices = [7,1,5,3,6,4] ⦠a) highest stock price on day 2 .. so we buy stock on day 1 and sell it on day 2 ( profit = 3 ) then we recurse on the remaining days : 1 2 3, b) Max price is 3 ( on day 5) so we keep buying stock on day 3 and day 4 and sell on day 5 ( profit = ( 3*2 - 3 = 3 ), The complexity for this turns out to be O(n^2) . Why did multiple nations decide to launch Mars projects at exactly the same time? Maximizing profit for given stock quotes (6) . What is the maximum profit you can obtain by planning your trading strategy optimally? He helpfully posted about each challenge on his blog and linked to his code on Github: Life Hacks. To learn more, see our tips on writing great answers. Sample Solution: Python Code: In stock trading, there is no time to fool around and incur losses. If ai==m then the profit from stocks bought at the the step is 0: we had decreasing or stable price after that point and did not buy. Is there a dynamic programming solution ? You are given the stock prices for a set of days . If you know the future prices of a stock, what's the best time to buy and sell? j > i How is this O(n) ? You are also given lists. You are also given K lists. Keep buying 1 unit of stock till that day. Contribute to umer7/hackerrank-python development by creating an account on GitHub. 29, May 16. I think I got a simpler algorithm than the accepted answer. Stock trade is easy if your travel backwards in time! Is that not O(n^2) ? Gross investment is just the sum of the two expressions. Opt-in alpha test for a new Stacks editor, Visual design changes to the review queues. b) If that day is the last day then quit: else: How can I defend reducing the strength of code reviews? Then we use [1:] to slice out the first number of each row because it is actually the count of items in that row and we don't need it. Hackerrank - Stock Maximize Solution Beeze Aal 06.Jul.2020 Your algorithms have become so good at predicting the market that you now know what the share price of Wooden Orange Toothpicks Inc. (WOT) will be for the next number of days. my solutions of Python hackerrank problems . We can process that information in O(N) itself. site design / logo © 2021 Stack Exchange Inc; user contributions licensed under cc by-sa. Strangeworks is on a mission to make quantum computing easy…well, easier. 2.Then find the profit by assuming you have bought all the stocks till smax Write a Python program to calculate the maximum profit from selling and buying values of stock. We use map and split function to convert the row input into list of integers. Your algorithms have become so good at predicting the market that can predict the share price of Wooden Orange Toothpicks Inc. Problem. "1 4 1 2 3" would show your algorithm better :). fixed. Just explain how you do for each a[i] find a[j] s.t. Then go to the next day (remember, backwards in time). Note that you need to take exactly one element from each list, not necessarily the largest element. j > i and it maximizes (a[j] - a[i]) The list consists of elements. Technical Scripter 2020. so please let me know if i need to improve/add things to this question. Note that m is the highest stock price we have seen (from the end). Here, S[i] is the price at which you should sell a[i]. if we take the XOR of any two numbers for maximum value their first bit will be fixed which will be same as first bit of ⦠Is it the highest price so far (from all we looked at yet)? Technical Scripter. Are airfoil profiles patented? An example problem In this article, we will show a very simplified version of the portfolio optimization problem, which can be cast into an LP framework and solved efficiently using simple Python scripting. To find the sell/buy days you just need to look at each day once: The trick is to start from the end. Only the code snippet of the function has been provided below, that you can paste in HackerRank editor below the // Complete the sockMerchant function below. Find a pair of overlapping intervals from a given Set Easy. Join Stack Overflow to learn, share knowledge, and build your career. Does this picture show an Arizona fire department extinguishing a fire in Mexico? Connect and share knowledge within a single location that is structured and easy to search. Why do guitarists specialize on particular techniques? If not, why? @MateuszDymczyk / PeitiPeterLi : This is 3 years late, but yes your are right. Making statements based on opinion; back them up with references or personal experience. You are also given K lists. Using this line of thought, you buy every stock before the maximum price, sell it at the maximum, and repeat the same thing for the remaining stock prices. P.S: this is the first time i am asking a question here. However our code works without unpacking the values. If you think code is easier to read than words, just skip my explanation, but here goes: Reading from the end, look at price of that day. Hackerrank - Maximize It! Or, maximizing the profit while keeping the risk below a certain threshold. continue the same way until the beginning. There is little update, Now one can only buy and sell at most N times, what will be the approach to this new condition ? The majority of the solutions are in Python ⦠You are also given lists. Exploring financial data with object-oriented programming and additive models. 1. smax = maximum stock price from the list 'calcprofit([1,2,100]) gives (197, [1, 1, 0])' : kind of curious how can profit be. Now problem reduces to previous answer+ i+1 to N... recursion is not required...linearly we can calculate! 1. smax = maximum stock price from the list 2. then find the profit by assuming you have bought all the stocks till smax and you sell it at the price of smax 3. then check if smax is the last element of the stock price list if yes then return profit as answer, if no then make a new list containing stock prices after smax to the last stock price and repeat steps 1-3 and keep adding profit of ⦠Else the prices increase, so buy. Contribute to BlakeBrown/HackerRank-Solutions development by creating an account on GitHub. 0.Start from end of array so that no need to recurse 1. smax = maximum stock price from the list 2.Then find the profit by assuming you have bought all the stocks till smax and you sell it at the price of smax Millions of developers and companies build, ship, and maintain their software on GitHub â the largest and most advanced development platform in the world. eval(ez_write_tag([[580,400],'thepoorcoder_com-medrectangle-4','ezslot_3',104,'0','0']));Before we get started, we must know that the follow 2 gives us equal results, (52 %1000 + 92 %1000 + 10 2 %1000) %1000 =206%1000 = 206, Also we should know the following python functions, The following code takes the value of K (no. Itâs easy to get carried away with the wealth of data and free open-source tools available f or data science. Should be readable for a C person). if you can explain the relation I would be grateful. of row ) times. Interview problem : Buy and sell stocks to maximize profit with constraint of not buying once you sell, Maximizing profit for given stock quotes, my solution in java, Stock Profit Maximization: Given Price Array, How to Maximize Profits with Boundaries, Easy interview question got harder: given numbers 1..100, find the missing number(s) given exactly k are missing. The whole problem is solved with one single reverse loop: calculating both the decisions and the profit of the trade. Another way to look at it: In pre-processing, for each element a[i] find a[j] s.t. Over the course of the next few (actually many) days, I will be posting the solutions to previous Hacker Rank challenges. You are given a function . S[i] is always larger than or equal to A[i] therefore you always get max(0,0) or (0, something_bigger_than_0). Its just I'm trying to visualize it from the beginning, that's all. 2 5 4 means we have 2 numbers in our row and 5,4 are the required numbers, 3 7 8 9 means we have 3 numbers in our row and 7,8,9 are the required numbers and so and so, eval(ez_write_tag([[300,250],'thepoorcoder_com-box-4','ezslot_1',108,'0','0']));As required by the question we square and find the remainder(or we can say modulus) after diving the squared number by M for each numbers in the row and then we append that list to nums variable. I was asked this question while interviewing for a startup and saw this again in the recent contest at, You are given the stock prices for a set of days . maximizing profit for given stock data via DP. Sell all the stocks on that day and split the array after that day and recurse on the remaining elements Worked alone for the same company during 7 years, now I feel like I lack a lot of basics skills, Finding the 8 outer corner vertices of an object, Short story: invention of a device to view the past, Short story about survivors on Earth after the atmosphere has frozen. In share trading, a buyer buys shares and sells on a future date. The cost of a stock on each day is given in an array, find the max profit that you can make by buying and selling in those days. Thanks for contributing an answer to Stack Overflow! ... #!/bin/python import math import os import random import re import sys # Complete the stockmax function below. **, Examples ( The input i.e the no of days can vary ), 5 3 2 => profit = 0 // since the price decreases each day ,the max profit we can make = 0, 1 3 1 2 =>profit = 3 // we buy at 1 sell at 3 , then we buy at 1 and sell at 2 ..total profit = 3. a) Find the day when the stock price was largest . After spending a little bit of time with the quandl financial library and the prophet modeling library, I decided to try some simple stock data exploration.Several days and 1000 lines of Python ⦠so, the Best you can do for a price at a[i] is Buy at a[i] and Sell at a[j]. @craftsmannadeem: first get one stock for 1$, then another one for 2$, then sell the two stocks at $100 each. You have to tell the maximum profit you can gain while traveling. Solution. The second and third lines are our constraints.This is basically what prevent us from, letâs say, maximizing our profit to the infinite.
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